Base | Representation |
---|---|
bin | 110010011011000001… |
… | …001111011010010101 |
3 | 12011202010201100110012 |
4 | 302123001033122111 |
5 | 1341334420320201 |
6 | 40512144410005 |
7 | 3624435550400 |
oct | 623301173225 |
9 | 164663640405 |
10 | 54140401301 |
11 | 20a62932908 |
12 | a5ab616905 |
13 | 514a7ac31c |
14 | 2898590d37 |
15 | 161d1005bb |
hex | c9b04f695 |
54140401301 has 12 divisors (see below), whose sum is σ = 62985948480. Its totient is φ = 46401417720.
The previous prime is 54140401291. The next prime is 54140401303. The reversal of 54140401301 is 10310404145.
54140401301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 54140401301 - 234 = 36960532117 is a prime.
It is a super-3 number, since 3×541404013013 (a number of 33 digits) contains 333 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54140401303) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 495146 + ... + 594516.
It is an arithmetic number, because the mean of its divisors is an integer number (5248829040).
Almost surely, 254140401301 is an apocalyptic number.
It is an amenable number.
54140401301 is a deficient number, since it is larger than the sum of its proper divisors (8845547179).
54140401301 is a wasteful number, since it uses less digits than its factorization.
54140401301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110504 (or 110497 counting only the distinct ones).
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 54140401301 its reverse (10310404145), we get a palindrome (64450805446).
The spelling of 54140401301 in words is "fifty-four billion, one hundred forty million, four hundred one thousand, three hundred one".
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