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5414113 is a prime number
BaseRepresentation
bin10100101001110011100001
3101012001202201
4110221303201
52341222423
6312013201
764006405
oct24516341
911161681
105414113
113068781
121991201
131177423
14a0d105
1571e2ad
hex529ce1

5414113 has 2 divisors, whose sum is σ = 5414114. Its totient is φ = 5414112.

The previous prime is 5414111. The next prime is 5414147. The reversal of 5414113 is 3114145.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4210704 + 1203409 = 2052^2 + 1097^2 .

It is a cyclic number.

It is not a de Polignac number, because 5414113 - 21 = 5414111 is a prime.

Together with 5414111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (5414111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2707056 + 2707057.

It is an arithmetic number, because the mean of its divisors is an integer number (2707057).

Almost surely, 25414113 is an apocalyptic number.

It is an amenable number.

5414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5414113 is an equidigital number, since it uses as much as digits as its factorization.

5414113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 240, while the sum is 19.

The square root of 5414113 is about 2326.8246603472. The cubic root of 5414113 is about 175.5937708263.

Adding to 5414113 its reverse (3114145), we get a palindrome (8528258).

Subtracting from 5414113 its reverse (3114145), we obtain a cube (2299968 = 1323).

The spelling of 5414113 in words is "five million, four hundred fourteen thousand, one hundred thirteen".