Base | Representation |
---|---|
bin | 11000100111101101110111… |
… | …10110111011010101101111 |
3 | 21002200211221022212001112001 |
4 | 30103312323312323111233 |
5 | 24044022201403114203 |
6 | 311052044112153131 |
7 | 14255400524051353 |
oct | 1423667366732557 |
9 | 232624838761461 |
10 | 54141214504303 |
11 | 16284184146963 |
12 | 60a4b1b2387a7 |
13 | 24296578b29a4 |
14 | d5263d59d463 |
15 | 63d50d28e91d |
hex | 313dbbdbb56f |
54141214504303 has 2 divisors, whose sum is σ = 54141214504304. Its totient is φ = 54141214504302.
The previous prime is 54141214504259. The next prime is 54141214504357. The reversal of 54141214504303 is 30340541214145.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54141214504303 - 217 = 54141214373231 is a prime.
It is a super-2 number, since 2×541412145043032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54141214504603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27070607252151 + 27070607252152.
It is an arithmetic number, because the mean of its divisors is an integer number (27070607252152).
Almost surely, 254141214504303 is an apocalyptic number.
54141214504303 is a deficient number, since it is larger than the sum of its proper divisors (1).
54141214504303 is an equidigital number, since it uses as much as digits as its factorization.
54141214504303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 54141214504303 its reverse (30340541214145), we get a palindrome (84481755718448).
The spelling of 54141214504303 in words is "fifty-four trillion, one hundred forty-one billion, two hundred fourteen million, five hundred four thousand, three hundred three".
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