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541500016117 is a prime number
BaseRepresentation
bin1111110000100111110…
…10101000010111110101
31220202201001210222000111
413320103322220113311
532332443001003432
61052432304343021
754056606123104
oct7702372502765
91822631728014
10541500016117
11199715707885
1288b43314a71
133c0a8bc9a28
141c2ccada03b
15e144169347
hex7e13ea85f5

541500016117 has 2 divisors, whose sum is σ = 541500016118. Its totient is φ = 541500016116.

The previous prime is 541500016087. The next prime is 541500016153. The reversal of 541500016117 is 711610005145.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 300699786321 + 240800229796 = 548361^2 + 490714^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-541500016117 is a prime.

It is a super-2 number, since 2×5415000161172 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (541500016157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270750008058 + 270750008059.

It is an arithmetic number, because the mean of its divisors is an integer number (270750008059).

Almost surely, 2541500016117 is an apocalyptic number.

It is an amenable number.

541500016117 is a deficient number, since it is larger than the sum of its proper divisors (1).

541500016117 is an equidigital number, since it uses as much as digits as its factorization.

541500016117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4200, while the sum is 31.

The spelling of 541500016117 in words is "five hundred forty-one billion, five hundred million, sixteen thousand, one hundred seventeen".