Base | Representation |
---|---|
bin | 1010000101100001… |
… | …00110001111111101 |
3 | 111222101021122211121 |
4 | 11002300212033331 |
5 | 42042220100013 |
6 | 2253154150541 |
7 | 251121524101 |
oct | 50260461775 |
9 | 14871248747 |
10 | 5415003133 |
11 | 23296a0001 |
12 | 1071582451 |
13 | 683b24087 |
14 | 39524d901 |
15 | 21a5d058d |
hex | 142c263fd |
5415003133 has 2 divisors, whose sum is σ = 5415003134. Its totient is φ = 5415003132.
The previous prime is 5415003103. The next prime is 5415003157. The reversal of 5415003133 is 3313005145.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4244131609 + 1170871524 = 65147^2 + 34218^2 .
It is a cyclic number.
It is not a de Polignac number, because 5415003133 - 213 = 5414994941 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5415003098 and 5415003107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5415003103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2707501566 + 2707501567.
It is an arithmetic number, because the mean of its divisors is an integer number (2707501567).
Almost surely, 25415003133 is an apocalyptic number.
It is an amenable number.
5415003133 is a deficient number, since it is larger than the sum of its proper divisors (1).
5415003133 is an equidigital number, since it uses as much as digits as its factorization.
5415003133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2700, while the sum is 25.
The square root of 5415003133 is about 73586.7048657568. The cubic root of 5415003133 is about 1756.0339340867.
Adding to 5415003133 its reverse (3313005145), we get a palindrome (8728008278).
The spelling of 5415003133 in words is "five billion, four hundred fifteen million, three thousand, one hundred thirty-three".
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