Base | Representation |
---|---|
bin | 11000101001011101110111… |
… | …11011000100110111010011 |
3 | 21002220121010221020112120111 |
4 | 30110232323323010313103 |
5 | 24101013323323242120 |
6 | 311135430524222151 |
7 | 14262626601011641 |
oct | 1424567373046723 |
9 | 232817127215514 |
10 | 54201345134035 |
11 | 162a7730335a80 |
12 | 60b470099a957 |
13 | 243221b419178 |
14 | d55505538191 |
15 | 63ed7c1e775a |
hex | 314bbbec4dd3 |
54201345134035 has 8 divisors (see below), whose sum is σ = 70954488175536. Its totient is φ = 39419160097440.
The previous prime is 54201345134021. The next prime is 54201345134051. The reversal of 54201345134035 is 53043154310245.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 54201345134035 - 213 = 54201345125843 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 492739501164 + ... + 492739501273.
It is an arithmetic number, because the mean of its divisors is an integer number (8869311021942).
Almost surely, 254201345134035 is an apocalyptic number.
54201345134035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
54201345134035 is a deficient number, since it is larger than the sum of its proper divisors (16753143041501).
54201345134035 is a wasteful number, since it uses less digits than its factorization.
54201345134035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 985479002453.
The product of its (nonzero) digits is 432000, while the sum is 40.
The spelling of 54201345134035 in words is "fifty-four trillion, two hundred one billion, three hundred forty-five million, one hundred thirty-four thousand, thirty-five".
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