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5420213 is a prime number
BaseRepresentation
bin10100101011010010110101
3101012101010122
4110223102311
52341421323
6312101325
764033241
oct24532265
911171118
105420213
113072317
121994845
13117a136
14a11421
15720ec8
hex52b4b5

5420213 has 2 divisors, whose sum is σ = 5420214. Its totient is φ = 5420212.

The previous prime is 5420179. The next prime is 5420227. The reversal of 5420213 is 3120245.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5373124 + 47089 = 2318^2 + 217^2 .

It is a cyclic number.

It is not a de Polignac number, because 5420213 - 210 = 5419189 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5420191 and 5420200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5420273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2710106 + 2710107.

It is an arithmetic number, because the mean of its divisors is an integer number (2710107).

Almost surely, 25420213 is an apocalyptic number.

It is an amenable number.

5420213 is a deficient number, since it is larger than the sum of its proper divisors (1).

5420213 is an equidigital number, since it uses as much as digits as its factorization.

5420213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 17.

The square root of 5420213 is about 2328.1350905822. The cubic root of 5420213 is about 175.6596923651.

Adding to 5420213 its reverse (3120245), we get a palindrome (8540458).

Subtracting from 5420213 its reverse (3120245), we obtain a cube (2299968 = 1323).

The spelling of 5420213 in words is "five million, four hundred twenty thousand, two hundred thirteen".