Base | Representation |
---|---|
bin | 100111011100010011101… |
… | …1110111000010111000001 |
3 | 201012020022121200011201211 |
4 | 1032320213132320113001 |
5 | 1202304011222243040 |
6 | 15310155430530121 |
7 | 1066435142240623 |
oct | 116704736702701 |
9 | 21166277604654 |
10 | 5420911134145 |
11 | 17aaaa5015501 |
12 | 736738206941 |
13 | 304260aa1760 |
14 | 14a532c48c13 |
15 | 96024d618ea |
hex | 4ee277b85c1 |
5420911134145 has 16 divisors (see below), whose sum is σ = 7007069405952. Its totient is φ = 4002229091520.
The previous prime is 5420911134127. The next prime is 5420911134151. The reversal of 5420911134145 is 5414311190245.
5420911134145 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5420911134145 - 213 = 5420911125953 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5420911134098 and 5420911134107.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9140341 + ... + 9715330.
It is an arithmetic number, because the mean of its divisors is an integer number (437941837872).
Almost surely, 25420911134145 is an apocalyptic number.
It is an amenable number.
5420911134145 is a deficient number, since it is larger than the sum of its proper divisors (1586158271807).
5420911134145 is a wasteful number, since it uses less digits than its factorization.
5420911134145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18860112.
The product of its (nonzero) digits is 86400, while the sum is 40.
The spelling of 5420911134145 in words is "five trillion, four hundred twenty billion, nine hundred eleven million, one hundred thirty-four thousand, one hundred forty-five".
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