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54212466373 = 134170189721
BaseRepresentation
bin110010011111010100…
…001001011011000101
312011221011022122010221
4302133110021123011
51342011342410443
640523241144341
73626302234552
oct623724113305
9164834278127
1054212466373
1120a9a58441a
12a60b78b0b1
13515c6c1a90
1428a3d8da29
1516245d7eed
hexc9f5096c5

54212466373 has 4 divisors (see below), whose sum is σ = 58382656108. Its totient is φ = 50042276640.

The previous prime is 54212466323. The next prime is 54212466379. The reversal of 54212466373 is 37366421245.

54212466373 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4486588324 + 49725878049 = 66982^2 + 222993^2 .

It is a cyclic number.

It is not a de Polignac number, because 54212466373 - 217 = 54212335301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54212466379) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2085094848 + ... + 2085094873.

It is an arithmetic number, because the mean of its divisors is an integer number (14595664027).

Almost surely, 254212466373 is an apocalyptic number.

It is an amenable number.

54212466373 is a deficient number, since it is larger than the sum of its proper divisors (4170189735).

54212466373 is a wasteful number, since it uses less digits than its factorization.

54212466373 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4170189734.

The product of its digits is 725760, while the sum is 43.

The spelling of 54212466373 in words is "fifty-four billion, two hundred twelve million, four hundred sixty-six thousand, three hundred seventy-three".

Divisors: 1 13 4170189721 54212466373