Base | Representation |
---|---|
bin | 1111110001110011001… |
… | …10010101110001001101 |
3 | 1220211100010102211010121 |
4 | 13320321212111301031 |
5 | 32340241322344440 |
6 | 1053015131104541 |
7 | 54111353634643 |
oct | 7707146256115 |
9 | 1824303384117 |
10 | 542132231245 |
11 | 199a0a569420 |
12 | 8909aba2151 |
13 | 3c179b94917 |
14 | 1c34ca6b193 |
15 | e17e8ec34a |
hex | 7e39995c4d |
542132231245 has 32 divisors (see below), whose sum is σ = 716157521280. Its totient is φ = 390692413440.
The previous prime is 542132231209. The next prime is 542132231261.
542132231245 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 542132231245 - 237 = 404693277773 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 542132231245.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 33671037 + ... + 33687133.
It is an arithmetic number, because the mean of its divisors is an integer number (22379922540).
Almost surely, 2542132231245 is an apocalyptic number.
542132231245 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
542132231245 is a deficient number, since it is larger than the sum of its proper divisors (174025290035).
542132231245 is a wasteful number, since it uses less digits than its factorization.
542132231245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21645.
The product of its digits is 57600, while the sum is 34.
It can be divided in two parts, 542132 and 231245, that added together give a palindrome (773377).
The spelling of 542132231245 in words is "five hundred forty-two billion, one hundred thirty-two million, two hundred thirty-one thousand, two hundred forty-five".
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