Base | Representation |
---|---|
bin | 11000101010000000101100… |
… | …10010101100110001111111 |
3 | 21002222101101220002022210111 |
4 | 30111000112102230301333 |
5 | 24101320121013123341 |
6 | 311152202032450451 |
7 | 14264161110333625 |
oct | 1425002622546177 |
9 | 232871356068714 |
10 | 54220041145471 |
11 | 163046547930a3 |
12 | 60b825a0a9a27 |
13 | 2433c0a8c0526 |
14 | d5639a581515 |
15 | 6405c3736681 |
hex | 3150164acc7f |
54220041145471 has 2 divisors, whose sum is σ = 54220041145472. Its totient is φ = 54220041145470.
The previous prime is 54220041145469. The next prime is 54220041145547. The reversal of 54220041145471 is 17454114002245.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54220041145471 - 21 = 54220041145469 is a prime.
It is a super-3 number, since 3×542200411454713 (a number of 42 digits) contains 333 as substring.
Together with 54220041145469, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54220041145411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27110020572735 + 27110020572736.
It is an arithmetic number, because the mean of its divisors is an integer number (27110020572736).
Almost surely, 254220041145471 is an apocalyptic number.
54220041145471 is a deficient number, since it is larger than the sum of its proper divisors (1).
54220041145471 is an equidigital number, since it uses as much as digits as its factorization.
54220041145471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 179200, while the sum is 40.
The spelling of 54220041145471 in words is "fifty-four trillion, two hundred twenty billion, forty-one million, one hundred forty-five thousand, four hundred seventy-one".
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