Base | Representation |
---|---|
bin | 111101101001000110011100… |
… | …0100010110111010000010101 |
3 | 2122002210211002100200002220002 |
4 | 1323102030320202313100111 |
5 | 1032032034103240342440 |
6 | 5201104022312021045 |
7 | 222131262526556366 |
oct | 17322147042672025 |
9 | 2562724070602802 |
10 | 542210505012245 |
11 | 147846202754023 |
12 | 50990041091785 |
13 | 1a37130101a754 |
14 | 97c71b2727b6d |
15 | 42a4215e33115 |
hex | 1ed23388b7415 |
542210505012245 has 4 divisors (see below), whose sum is σ = 650652606014700. Its totient is φ = 433768404009792.
The previous prime is 542210505012109. The next prime is 542210505012247.
542210505012245 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 305450212853956 + 236760292158289 = 17477134^2 + 15387017^2 .
It is a cyclic number.
It is not a de Polignac number, because 542210505012245 - 232 = 542206210044949 is a prime.
It is a super-3 number, since 3×5422105050122453 (a number of 45 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 542210505012199 and 542210505012208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (542210505012247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54221050501220 + ... + 54221050501229.
It is an arithmetic number, because the mean of its divisors is an integer number (162663151503675).
Almost surely, 2542210505012245 is an apocalyptic number.
It is an amenable number.
542210505012245 is a deficient number, since it is larger than the sum of its proper divisors (108442101002455).
542210505012245 is a wasteful number, since it uses less digits than its factorization.
542210505012245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108442101002454.
The product of its (nonzero) digits is 160000, while the sum is 38.
It can be divided in two parts, 54221050 and 5012245, that added together give a palindrome (59233295).
The spelling of 542210505012245 in words is "five hundred forty-two trillion, two hundred ten billion, five hundred five million, twelve thousand, two hundred forty-five".
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