Base | Representation |
---|---|
bin | 11000101010111111000101… |
… | …11111010001110010111000 |
3 | 21010002120212111101022021112 |
4 | 30111133202333101302320 |
5 | 24102342222234421202 |
6 | 311215422100455452 |
7 | 14266455205244264 |
oct | 1425374277216270 |
9 | 233076774338245 |
10 | 54253540154552 |
11 | 16317885037472 |
12 | 61028489aa588 |
13 | 2437118b65bab |
14 | d57c575ab0a4 |
15 | 6413d4623b52 |
hex | 3157e2fd1cb8 |
54253540154552 has 64 divisors (see below), whose sum is σ = 102777776640000. Its totient is φ = 26847937569024.
The previous prime is 54253540154533. The next prime is 54253540154563. The reversal of 54253540154552 is 25545104535245.
It is a super-3 number, since 3×542535401545523 (a number of 42 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 54253540154552.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 238570133 + ... + 238797435.
It is an arithmetic number, because the mean of its divisors is an integer number (1605902760000).
Almost surely, 254253540154552 is an apocalyptic number.
It is an amenable number.
54253540154552 is a deficient number, since it is larger than the sum of its proper divisors (48524236485448).
54253540154552 is a wasteful number, since it uses less digits than its factorization.
54253540154552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 228300 (or 228296 counting only the distinct ones).
The product of its (nonzero) digits is 12000000, while the sum is 50.
Adding to 54253540154552 its reverse (25545104535245), we get a palindrome (79798644689797).
The spelling of 54253540154552 in words is "fifty-four trillion, two hundred fifty-three billion, five hundred forty million, one hundred fifty-four thousand, five hundred fifty-two".
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