Base | Representation |
---|---|
bin | 1111110011101011100… |
… | …11001110010001000001 |
3 | 1220220221111221122112002 |
4 | 13321311303032101001 |
5 | 32344323403210340 |
6 | 1053303251113345 |
7 | 54145366606544 |
oct | 7716563162101 |
9 | 1826844848462 |
10 | 543142241345 |
11 | 19a3886a9a10 |
12 | 893212a2855 |
13 | 3c2ab1c8132 |
14 | 1c406c6285b |
15 | e1dd409715 |
hex | 7e75cce441 |
543142241345 has 96 divisors (see below), whose sum is σ = 794380245120. Its totient is φ = 352899348480.
The previous prime is 543142241329. The next prime is 543142241363.
543142241345 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 543142241345 - 24 = 543142241329 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 543142241299 and 543142241308.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 24748217 + ... + 24770153.
It is an arithmetic number, because the mean of its divisors is an integer number (8274794220).
Almost surely, 2543142241345 is an apocalyptic number.
543142241345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
543142241345 is a deficient number, since it is larger than the sum of its proper divisors (251238003775).
543142241345 is a wasteful number, since it uses less digits than its factorization.
543142241345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22063 (or 22044 counting only the distinct ones).
The product of its digits is 230400, while the sum is 38.
It can be divided in two parts, 543142 and 241345, that added together give a palindrome (784487).
The spelling of 543142241345 in words is "five hundred forty-three billion, one hundred forty-two million, two hundred forty-one thousand, three hundred forty-five".
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