Base | Representation |
---|---|
bin | 110010100101101110… |
… | …011010010000000111 |
3 | 12012012122200122020002 |
4 | 302211232122100013 |
5 | 1342221410424333 |
6 | 40542042231515 |
7 | 3632046334520 |
oct | 624556322007 |
9 | 165178618202 |
10 | 54320014343 |
11 | 21045260841 |
12 | a63b7b559b |
13 | 5178a7902a |
14 | 28b4387847 |
15 | 162dc7e0e8 |
hex | ca5b9a407 |
54320014343 has 8 divisors (see below), whose sum is σ = 63251337888. Its totient is φ = 45681521184.
The previous prime is 54320014327. The next prime is 54320014367. The reversal of 54320014343 is 34341002345.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54320014343 - 24 = 54320014327 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54320014373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73207196 + ... + 73207937.
It is an arithmetic number, because the mean of its divisors is an integer number (7906417236).
Almost surely, 254320014343 is an apocalyptic number.
54320014343 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
54320014343 is a deficient number, since it is larger than the sum of its proper divisors (8931323545).
54320014343 is a wasteful number, since it uses less digits than its factorization.
54320014343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 146415193.
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 54320014343 its reverse (34341002345), we get a palindrome (88661016688).
The spelling of 54320014343 in words is "fifty-four billion, three hundred twenty million, fourteen thousand, three hundred forty-three".
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