5433114113345 has 4 divisors (see below), whose sum is σ = 6519736936020. Its totient is φ = 4346491290672.

The previous prime is 5433114113327. The next prime is 5433114113513.

5433114113345 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3229525279744 + 2203588833601 = 1797088^2 + 1484449^2 .

It is a cyclic number.

It is not a de Polignac number, because 5433114113345 - 2³⁶ = 5364394636609 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5433114113299 and 5433114113308.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 543311411330 + ... + 543311411339.

It is an arithmetic number, because the mean of its divisors is an integer number (1629934234005).

Almost surely, 2^{5433114113345} is an apocalyptic number.

It is an amenable number.

5433114113345 is a deficient number, since it is larger than the sum of its proper divisors (1086622822675).

5433114113345 is a wasteful number, since it uses less digits than its factorization.

5433114113345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1086622822674.

The product of its digits is 129600, while the sum is 38.

The spelling of 5433114113345 in words is "five trillion, four hundred thirty-three billion, one hundred fourteen million, one hundred thirteen thousand, three hundred forty-five".