543314041 has 4 divisors (see below), whose sum is σ = 543984784. Its totient is φ = 542643300.

The previous prime is 543314021. The next prime is 543314053. The reversal of 543314041 is 140413345.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 140413345 = 5 ⋅28082669.

It is a cyclic number.

It is not a de Polignac number, because 543314041 - 2⁷ = 543313913 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 543313997 and 543314015.

It is not an unprimeable number, because it can be changed into a prime (543314011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334155 + ... + 335776.

It is an arithmetic number, because the mean of its divisors is an integer number (135996196).

Almost surely, 2^543314041 is an apocalyptic number.

It is an amenable number.

543314041 is a deficient number, since it is larger than the sum of its proper divisors (670743).

543314041 is an equidigital number, since it uses as much as digits as its factorization.

543314041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 670742.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 543314041 is about 23309.0978160889. The cubic root of 543314041 is about 815.9877574296.

Adding to 543314041 its reverse (140413345), we get a palindrome (683727386).

The spelling of 543314041 in words is "five hundred forty-three million, three hundred fourteen thousand, forty-one".