Base | Representation |
---|---|
bin | 11000101101011001100011… |
… | …01011100101001111000111 |
3 | 21010101111220122200020102211 |
4 | 30112230301223211033013 |
5 | 24110222034440114431 |
6 | 311321454411044251 |
7 | 14305452151660435 |
oct | 1426546153451707 |
9 | 233344818606384 |
10 | 54336464769991 |
11 | 16349a688a53a8 |
12 | 6116930140687 |
13 | 2441ba2b79891 |
14 | d5bc82927d55 |
15 | 6436397452b1 |
hex | 316b31ae53c7 |
54336464769991 has 2 divisors, whose sum is σ = 54336464769992. Its totient is φ = 54336464769990.
The previous prime is 54336464769989. The next prime is 54336464770057. The reversal of 54336464769991 is 19996746463345.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54336464769991 - 21 = 54336464769989 is a prime.
Together with 54336464769989, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54336464769091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27168232384995 + 27168232384996.
It is an arithmetic number, because the mean of its divisors is an integer number (27168232384996).
Almost surely, 254336464769991 is an apocalyptic number.
54336464769991 is a deficient number, since it is larger than the sum of its proper divisors (1).
54336464769991 is an equidigital number, since it uses as much as digits as its factorization.
54336464769991 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3174474240, while the sum is 76.
The spelling of 54336464769991 in words is "fifty-four trillion, three hundred thirty-six billion, four hundred sixty-four million, seven hundred sixty-nine thousand, nine hundred ninety-one".
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