Base | Representation |
---|---|
bin | 110010100111001011… |
… | …001110000101011101 |
3 | 12012021100110201002211 |
4 | 302213023032011131 |
5 | 1342244123001101 |
6 | 40544311520421 |
7 | 3632463205261 |
oct | 624713160535 |
9 | 165240421084 |
10 | 54344343901 |
11 | 21057a68a11 |
12 | a647989111 |
13 | 5180b17013 |
14 | 28b76bc0a1 |
15 | 1630e87c51 |
hex | ca72ce15d |
54344343901 has 4 divisors (see below), whose sum is σ = 54352994112. Its totient is φ = 54335693692.
The previous prime is 54344343899. The next prime is 54344343931. The reversal of 54344343901 is 10934344345.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10934344345 = 5 ⋅2186868869.
It is a cyclic number.
It is not a de Polignac number, because 54344343901 - 21 = 54344343899 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54344343931) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4315675 + ... + 4328248.
It is an arithmetic number, because the mean of its divisors is an integer number (13588248528).
Almost surely, 254344343901 is an apocalyptic number.
It is an amenable number.
54344343901 is a deficient number, since it is larger than the sum of its proper divisors (8650211).
54344343901 is an equidigital number, since it uses as much as digits as its factorization.
54344343901 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8650210.
The product of its (nonzero) digits is 311040, while the sum is 40.
The spelling of 54344343901 in words is "fifty-four billion, three hundred forty-four million, three hundred forty-three thousand, nine hundred one".
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