5440400012133 has 12 divisors (see below), whose sum is σ = 7906566345600. Its totient is φ = 3604682215656.

The previous prime is 5440400012083. The next prime is 5440400012147. The reversal of 5440400012133 is 3312100040445.

It is a happy number.

5440400012133 is a `hidden beast` number, since 5 + 4 + 40 + 400 + 0 + 1 + 213 + 3 = 666.

5440400012133 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 5440400012133 - 2⁴² = 1042353501029 is a prime.

It is a super-3 number, since 3×5440400012133³ (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5440400012097 and 5440400012106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5440400012183) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1854258933 + ... + 1854261866.

It is an arithmetic number, because the mean of its divisors is an integer number (658880528800).

Almost surely, 2^{5440400012133} is an apocalyptic number.

It is an amenable number.

5440400012133 is a deficient number, since it is larger than the sum of its proper divisors (2466166333467).

5440400012133 is a wasteful number, since it uses less digits than its factorization.

5440400012133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3708520968 (or 3708520965 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 27.

Adding to 5440400012133 its reverse (3312100040445), we get a palindrome (8752500052578).

The spelling of 5440400012133 in words is "five trillion, four hundred forty billion, four hundred million, twelve thousand, one hundred thirty-three".