Base | Representation |
---|---|
bin | 1111110101010111111… |
… | …11110110011100011111 |
3 | 1221000021212220212010212 |
4 | 13322223333312130133 |
5 | 32403204142140221 |
6 | 1053533412123035 |
7 | 54210050425544 |
oct | 7725377663437 |
9 | 1830255825125 |
10 | 544051521311 |
11 | 19a80499a461 |
12 | 8953590647b |
13 | 3c3c46c070c |
14 | 1c491916bcb |
15 | e24316ab5b |
hex | 7eabff671f |
544051521311 has 2 divisors, whose sum is σ = 544051521312. Its totient is φ = 544051521310.
The previous prime is 544051521227. The next prime is 544051521313. The reversal of 544051521311 is 113125150445.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-544051521311 is a prime.
Together with 544051521313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (544051521313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272025760655 + 272025760656.
It is an arithmetic number, because the mean of its divisors is an integer number (272025760656).
Almost surely, 2544051521311 is an apocalyptic number.
544051521311 is a deficient number, since it is larger than the sum of its proper divisors (1).
544051521311 is an equidigital number, since it uses as much as digits as its factorization.
544051521311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 544051521311 its reverse (113125150445), we get a palindrome (657176671756).
The spelling of 544051521311 in words is "five hundred forty-four billion, fifty-one million, five hundred twenty-one thousand, three hundred eleven".
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