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5443260623447 is a prime number
BaseRepresentation
bin100111100110101101110…
…0111011010101001010111
3201021101000012011212101212
41033031123213122221113
51203140244204422242
615324333250012035
71101156033615563
oct117153347325127
921241005155355
105443260623447
111809523797619
1273ab34b7701b
133063b315b33a
1414b6531a26a3
15968d1ec7782
hex4f35b9daa57

5443260623447 has 2 divisors, whose sum is σ = 5443260623448. Its totient is φ = 5443260623446.

The previous prime is 5443260623417. The next prime is 5443260623461. The reversal of 5443260623447 is 7443260623445.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5443260623447 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5443260623395 and 5443260623404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5443260623417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2721630311723 + 2721630311724.

It is an arithmetic number, because the mean of its divisors is an integer number (2721630311724).

Almost surely, 25443260623447 is an apocalyptic number.

5443260623447 is a deficient number, since it is larger than the sum of its proper divisors (1).

5443260623447 is an equidigital number, since it uses as much as digits as its factorization.

5443260623447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11612160, while the sum is 50.

The spelling of 5443260623447 in words is "five trillion, four hundred forty-three billion, two hundred sixty million, six hundred twenty-three thousand, four hundred forty-seven".