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544331421293 = 1149484674663
BaseRepresentation
bin1111110101111001010…
…11100101011001101101
31221001000101121020201212
413322330223211121231
532404242320440133
61054021251244205
754220016511512
oct7727453453155
91831011536655
10544331421293
1119a938995460
12895b35a9665
133c43a6a16ca
141c4bab77309
15e25ca09148
hex7ebcae566d

544331421293 has 4 divisors (see below), whose sum is σ = 593816095968. Its totient is φ = 494846746620.

The previous prime is 544331421269. The next prime is 544331421301. The reversal of 544331421293 is 392124133445.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 544331421293 - 26 = 544331421229 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 544331421293.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (544331421233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24742337321 + ... + 24742337342.

It is an arithmetic number, because the mean of its divisors is an integer number (148454023992).

Almost surely, 2544331421293 is an apocalyptic number.

It is an amenable number.

544331421293 is a deficient number, since it is larger than the sum of its proper divisors (49484674675).

544331421293 is a wasteful number, since it uses less digits than its factorization.

544331421293 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49484674674.

The product of its digits is 311040, while the sum is 41.

The spelling of 544331421293 in words is "five hundred forty-four billion, three hundred thirty-one million, four hundred twenty-one thousand, two hundred ninety-three".

Divisors: 1 11 49484674663 544331421293