Base | Representation |
---|---|
bin | 1010001000111110… |
… | …01100001110100101 |
3 | 112001101211120120011 |
4 | 11010133030032211 |
5 | 42122130311113 |
6 | 2300111410221 |
7 | 251623122115 |
oct | 50437141645 |
9 | 15041746504 |
10 | 5443994533 |
11 | 2343aa173a |
12 | 107b223971 |
13 | 689b34c53 |
14 | 399039045 |
15 | 21ce0a63d |
hex | 1447cc3a5 |
5443994533 has 2 divisors, whose sum is σ = 5443994534. Its totient is φ = 5443994532.
The previous prime is 5443994531. The next prime is 5443994603. The reversal of 5443994533 is 3354993445.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5440242564 + 3751969 = 73758^2 + 1937^2 .
It is a cyclic number.
It is not a de Polignac number, because 5443994533 - 21 = 5443994531 is a prime.
Together with 5443994531, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5443994531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2721997266 + 2721997267.
It is an arithmetic number, because the mean of its divisors is an integer number (2721997267).
Almost surely, 25443994533 is an apocalyptic number.
It is an amenable number.
5443994533 is a deficient number, since it is larger than the sum of its proper divisors (1).
5443994533 is an equidigital number, since it uses as much as digits as its factorization.
5443994533 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3499200, while the sum is 49.
The square root of 5443994533 is about 73783.4299351826. The cubic root of 5443994533 is about 1759.1622361214.
The spelling of 5443994533 in words is "five billion, four hundred forty-three million, nine hundred ninety-four thousand, five hundred thirty-three".
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