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544413101693 is a prime number
BaseRepresentation
bin1111110110000011000…
…11001010111001111101
31221001020002022001011212
413323001203022321331
532404424223223233
61054033330054205
754222031004006
oct7730143127175
91831202261155
10544413101693
1119a98000411a
1289616a1a365
133c45159c8c6
141c4c795a1ad
15e264c90a48
hex7ec18cae7d

544413101693 has 2 divisors, whose sum is σ = 544413101694. Its totient is φ = 544413101692.

The previous prime is 544413101647. The next prime is 544413101699. The reversal of 544413101693 is 396101314445.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 493930651204 + 50482450489 = 702802^2 + 224683^2 .

It is a cyclic number.

It is not a de Polignac number, because 544413101693 - 28 = 544413101437 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 544413101693.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (544413101699) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272206550846 + 272206550847.

It is an arithmetic number, because the mean of its divisors is an integer number (272206550847).

Almost surely, 2544413101693 is an apocalyptic number.

It is an amenable number.

544413101693 is a deficient number, since it is larger than the sum of its proper divisors (1).

544413101693 is an equidigital number, since it uses as much as digits as its factorization.

544413101693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 544413101693 in words is "five hundred forty-four billion, four hundred thirteen million, one hundred one thousand, six hundred ninety-three".