Base | Representation |
---|---|
bin | 110010101100111101… |
… | …000111100000000101 |
3 | 12012112002221002212201 |
4 | 302230331013200011 |
5 | 1342443433411323 |
6 | 41002054114501 |
7 | 3635051334013 |
oct | 625475074005 |
9 | 165462832781 |
10 | 54441310213 |
11 | 210a7778164 |
12 | a67434ba31 |
13 | 5197c37a34 |
14 | 28c651d8b3 |
15 | 163973d8ad |
hex | cacf47805 |
54441310213 has 2 divisors, whose sum is σ = 54441310214. Its totient is φ = 54441310212.
The previous prime is 54441310181. The next prime is 54441310219. The reversal of 54441310213 is 31201314445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28482300289 + 25959009924 = 168767^2 + 161118^2 .
It is a cyclic number.
It is not a de Polignac number, because 54441310213 - 25 = 54441310181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54441310219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27220655106 + 27220655107.
It is an arithmetic number, because the mean of its divisors is an integer number (27220655107).
Almost surely, 254441310213 is an apocalyptic number.
It is an amenable number.
54441310213 is a deficient number, since it is larger than the sum of its proper divisors (1).
54441310213 is an equidigital number, since it uses as much as digits as its factorization.
54441310213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 54441310213 its reverse (31201314445), we get a palindrome (85642624658).
The spelling of 54441310213 in words is "fifty-four billion, four hundred forty-one million, three hundred ten thousand, two hundred thirteen".
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