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54452032143 = 318150677381
BaseRepresentation
bin110010101101100110…
…000001001010001111
312012112212002211121020
4302231212001022033
51343004210012033
641003120005223
73635241431205
oct625546011217
9165485084536
1054452032143
1121102830763
12a677a60813
13519a220082
1428c7b11075
15163a65a6b3
hexcad98128f

54452032143 has 4 divisors (see below), whose sum is σ = 72602709528. Its totient is φ = 36301354760.

The previous prime is 54452032081. The next prime is 54452032199. The reversal of 54452032143 is 34123025445.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54452032143 - 214 = 54452015759 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54452032643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9075338688 + ... + 9075338693.

It is an arithmetic number, because the mean of its divisors is an integer number (18150677382).

Almost surely, 254452032143 is an apocalyptic number.

54452032143 is a deficient number, since it is larger than the sum of its proper divisors (18150677385).

54452032143 is a wasteful number, since it uses less digits than its factorization.

54452032143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18150677384.

The product of its (nonzero) digits is 57600, while the sum is 33.

Adding to 54452032143 its reverse (34123025445), we get a palindrome (88575057588).

The spelling of 54452032143 in words is "fifty-four billion, four hundred fifty-two million, thirty-two thousand, one hundred forty-three".

Divisors: 1 3 18150677381 54452032143