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54503045341501 is a prime number
BaseRepresentation
bin11000110010001111110101…
…01010000010000100111101
321010222102212221102001111111
430121013322222002010331
524120434214101412001
6311530204154522021
714323500162322351
oct1431077252020475
9233872787361444
1054503045341501
1116403680227309
12614307b736311
1324547cc5678a3
14d65d663b7461
15647b38c9b851
hex3191faa8213d

54503045341501 has 2 divisors, whose sum is σ = 54503045341502. Its totient is φ = 54503045341500.

The previous prime is 54503045341499. The next prime is 54503045341561. The reversal of 54503045341501 is 10514354030545.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 46180247316025 + 8322798025476 = 6795605^2 + 2884926^2 .

It is a cyclic number.

It is not a de Polignac number, because 54503045341501 - 21 = 54503045341499 is a prime.

It is a super-3 number, since 3×545030453415013 (a number of 42 digits) contains 333 as substring.

Together with 54503045341499, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54503045341561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27251522670750 + 27251522670751.

It is an arithmetic number, because the mean of its divisors is an integer number (27251522670751).

Almost surely, 254503045341501 is an apocalyptic number.

It is an amenable number.

54503045341501 is a deficient number, since it is larger than the sum of its proper divisors (1).

54503045341501 is an equidigital number, since it uses as much as digits as its factorization.

54503045341501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360000, while the sum is 40.

The spelling of 54503045341501 in words is "fifty-four trillion, five hundred three billion, forty-five million, three hundred forty-one thousand, five hundred one".