Base | Representation |
---|---|
bin | 1111110111001110001… |
… | …11010110101010010101 |
3 | 1221002212000012200010022 |
4 | 13323213013112222111 |
5 | 32412222044002041 |
6 | 1054220042234525 |
7 | 54243452661131 |
oct | 7734707265225 |
9 | 1832760180108 |
10 | 545043344021 |
11 | 1a0173838550 |
12 | 89771ab5a45 |
13 | 3c522026867 |
14 | 1c5475363c1 |
15 | e2a028424b |
hex | 7ee71d6a95 |
545043344021 has 4 divisors (see below), whose sum is σ = 594592738944. Its totient is φ = 495493949100.
The previous prime is 545043343981. The next prime is 545043344023. The reversal of 545043344021 is 120443340545.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-545043344021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (545043344023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24774697445 + ... + 24774697466.
It is an arithmetic number, because the mean of its divisors is an integer number (148648184736).
Almost surely, 2545043344021 is an apocalyptic number.
It is an amenable number.
545043344021 is a deficient number, since it is larger than the sum of its proper divisors (49549394923).
545043344021 is a wasteful number, since it uses less digits than its factorization.
545043344021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49549394922.
The product of its (nonzero) digits is 115200, while the sum is 35.
Adding to 545043344021 its reverse (120443340545), we get a palindrome (665486684566).
The spelling of 545043344021 in words is "five hundred forty-five billion, forty-three million, three hundred forty-four thousand, twenty-one".
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