Base | Representation |
---|---|
bin | 110010110011000101… |
… | …000011100000011111 |
3 | 12012210021021001021101 |
4 | 302303011003200133 |
5 | 1343201234214203 |
6 | 41020204213531 |
7 | 3640436545324 |
oct | 626305034037 |
9 | 165707231241 |
10 | 54544054303 |
11 | 2114a773332 |
12 | a6a283a2a7 |
13 | 51b32cc55b |
14 | 28d6026b4b |
15 | 164378641d |
hex | cb314381f |
54544054303 has 2 divisors, whose sum is σ = 54544054304. Its totient is φ = 54544054302.
The previous prime is 54544054261. The next prime is 54544054399. The reversal of 54544054303 is 30345044545.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54544054303 - 225 = 54510499871 is a prime.
It is a super-2 number, since 2×545440543032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54544054403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27272027151 + 27272027152.
It is an arithmetic number, because the mean of its divisors is an integer number (27272027152).
Almost surely, 254544054303 is an apocalyptic number.
54544054303 is a deficient number, since it is larger than the sum of its proper divisors (1).
54544054303 is an equidigital number, since it uses as much as digits as its factorization.
54544054303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288000, while the sum is 37.
Adding to 54544054303 its reverse (30345044545), we get a palindrome (84889098848).
The spelling of 54544054303 in words is "fifty-four billion, five hundred forty-four million, fifty-four thousand, three hundred three".
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