Base | Representation |
---|---|
bin | 11000110110101111010111… |
… | …00110000110100010111101 |
3 | 21011112012022222112011110001 |
4 | 30123113223212012202331 |
5 | 24131001334314210040 |
6 | 312125133532514301 |
7 | 14340603415652566 |
oct | 1433275346064275 |
9 | 234465288464401 |
10 | 54657411475645 |
11 | 16463094953690 |
12 | 6168b8061b991 |
13 | 2466230550574 |
14 | d6d60b98916d |
15 | 64bb70d2559a |
hex | 31b5eb9868bd |
54657411475645 has 32 divisors (see below), whose sum is σ = 72762127461504. Its totient is φ = 39078959673600.
The previous prime is 54657411475621. The next prime is 54657411475649.
54657411475645 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 54657411475645 - 213 = 54657411467453 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54657411475649) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2271214 + ... + 10699216.
It is an arithmetic number, because the mean of its divisors is an integer number (2273816483172).
Almost surely, 254657411475645 is an apocalyptic number.
54657411475645 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54657411475645 is a deficient number, since it is larger than the sum of its proper divisors (18104715985859).
54657411475645 is a wasteful number, since it uses less digits than its factorization.
54657411475645 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8430013.
The product of its digits is 282240000, while the sum is 64.
The spelling of 54657411475645 in words is "fifty-four trillion, six hundred fifty-seven billion, four hundred eleven million, four hundred seventy-five thousand, six hundred forty-five".
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