Base | Representation |
---|---|
bin | 110011000100101110… |
… | …101111100000111011 |
3 | 12020112220111120010012 |
4 | 303010232233200323 |
5 | 1344303042221011 |
6 | 41105423412135 |
7 | 3650663652551 |
oct | 630456574073 |
9 | 166486446105 |
10 | 54840195131 |
11 | 21291951317 |
12 | a765a5404b |
13 | 522c778907 |
14 | 29234b3bd1 |
15 | 165e781a8b |
hex | cc4baf83b |
54840195131 has 2 divisors, whose sum is σ = 54840195132. Its totient is φ = 54840195130.
The previous prime is 54840195089. The next prime is 54840195133. The reversal of 54840195131 is 13159104845.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54840195131 is a prime.
It is a super-2 number, since 2×548401951312 (a number of 22 digits) contains 22 as substring.
Together with 54840195133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (54840195133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27420097565 + 27420097566.
It is an arithmetic number, because the mean of its divisors is an integer number (27420097566).
Almost surely, 254840195131 is an apocalyptic number.
54840195131 is a deficient number, since it is larger than the sum of its proper divisors (1).
54840195131 is an equidigital number, since it uses as much as digits as its factorization.
54840195131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 41.
Adding to 54840195131 its reverse (13159104845), we get a palindrome (67999299976).
The spelling of 54840195131 in words is "fifty-four billion, eight hundred forty million, one hundred ninety-five thousand, one hundred thirty-one".
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