Base | Representation |
---|---|
bin | 110011000110101011… |
… | …111000100000100011 |
3 | 12020122012020012220021 |
4 | 303012223320200203 |
5 | 1344334441444341 |
6 | 41112554454311 |
7 | 3651542542516 |
oct | 630653704043 |
9 | 166565205807 |
10 | 54872999971 |
11 | 212a9418059 |
12 | a774a34397 |
13 | 52364c346a |
14 | 29279b2d7d |
15 | 16625b19d1 |
hex | cc6af8823 |
54872999971 has 2 divisors, whose sum is σ = 54872999972. Its totient is φ = 54872999970.
The previous prime is 54872999969. The next prime is 54873000073. The reversal of 54872999971 is 17999927845.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54872999971 - 21 = 54872999969 is a prime.
It is a super-3 number, since 3×548729999713 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 54872999969, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 54872999971.
It is not a weakly prime, because it can be changed into another prime (54872999471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27436499985 + 27436499986.
It is an arithmetic number, because the mean of its divisors is an integer number (27436499986).
Almost surely, 254872999971 is an apocalyptic number.
54872999971 is a deficient number, since it is larger than the sum of its proper divisors (1).
54872999971 is an equidigital number, since it uses as much as digits as its factorization.
54872999971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 102876480, while the sum is 70.
The spelling of 54872999971 in words is "fifty-four billion, eight hundred seventy-two million, nine hundred ninety-nine thousand, nine hundred seventy-one".
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