Base | Representation |
---|---|
bin | 1010001110100000… |
… | …10110011101101101 |
3 | 112011122020001012121 |
4 | 11013100112131231 |
5 | 42221022422244 |
6 | 2304451032541 |
7 | 253025635615 |
oct | 50720263555 |
9 | 15148201177 |
10 | 5490435949 |
11 | 2368231879 |
12 | 109289b751 |
13 | 69664568b |
14 | 3a1287a45 |
15 | 222030c84 |
hex | 14741676d |
5490435949 has 2 divisors, whose sum is σ = 5490435950. Its totient is φ = 5490435948.
The previous prime is 5490435917. The next prime is 5490436027. The reversal of 5490435949 is 9495340945.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2940892900 + 2549543049 = 54230^2 + 50493^2 .
It is a cyclic number.
It is not a de Polignac number, because 5490435949 - 25 = 5490435917 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5490435896 and 5490435905.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5490432949) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2745217974 + 2745217975.
It is an arithmetic number, because the mean of its divisors is an integer number (2745217975).
Almost surely, 25490435949 is an apocalyptic number.
It is an amenable number.
5490435949 is a deficient number, since it is larger than the sum of its proper divisors (1).
5490435949 is an equidigital number, since it uses as much as digits as its factorization.
5490435949 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3499200, while the sum is 52.
The square root of 5490435949 is about 74097.4759961498. The cubic root of 5490435949 is about 1764.1504094311.
The spelling of 5490435949 in words is "five billion, four hundred ninety million, four hundred thirty-five thousand, nine hundred forty-nine".
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