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54943472293 is a prime number
BaseRepresentation
bin110011001010111000…
…101101101010100101
312020211002211120202021
4303022320231222211
51400011012103133
641123553143141
73653356544263
oct631270555245
9166732746667
1054943472293
1121335180a46
12a79455aab1
135247c98c68
1429330b9433
15166888252d
hexccae2daa5

54943472293 has 2 divisors, whose sum is σ = 54943472294. Its totient is φ = 54943472292.

The previous prime is 54943472279. The next prime is 54943472327. The reversal of 54943472293 is 39227434945.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51402865284 + 3540607009 = 226722^2 + 59503^2 .

It is a cyclic number.

It is not a de Polignac number, because 54943472293 - 225 = 54909917861 is a prime.

It is a super-2 number, since 2×549434722932 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 54943472293.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54943472093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27471736146 + 27471736147.

It is an arithmetic number, because the mean of its divisors is an integer number (27471736147).

Almost surely, 254943472293 is an apocalyptic number.

It is an amenable number.

54943472293 is a deficient number, since it is larger than the sum of its proper divisors (1).

54943472293 is an equidigital number, since it uses as much as digits as its factorization.

54943472293 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6531840, while the sum is 52.

The spelling of 54943472293 in words is "fifty-four billion, nine hundred forty-three million, four hundred seventy-two thousand, two hundred ninety-three".