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55000000003 = 132325443787
BaseRepresentation
bin110011001110010000…
…010110011000000011
312020222001012111012011
4303032100112120003
51400120000000003
641133332513351
73654644200144
oct631620263003
9166861174164
1055000000003
1121364080063
12a7ab47b857
1352568cb600
14293a7d1acb
15166d7eb46d
hexcce416603

55000000003 has 6 divisors (see below), whose sum is σ = 59556213204. Its totient is φ = 50769230616.

The previous prime is 55000000001. The next prime is 55000000021. The reversal of 55000000003 is 30000000055.

It is not a de Polignac number, because 55000000003 - 21 = 55000000001 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 55000000003.

It is not an unprimeable number, because it can be changed into a prime (55000000001) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 162721725 + ... + 162722062.

It is an arithmetic number, because the mean of its divisors is an integer number (9926035534).

Almost surely, 255000000003 is an apocalyptic number.

55000000003 is a deficient number, since it is larger than the sum of its proper divisors (4556213201).

55000000003 is a wasteful number, since it uses less digits than its factorization.

55000000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 325443813 (or 325443800 counting only the distinct ones).

The product of its (nonzero) digits is 75, while the sum is 13.

Adding to 55000000003 its reverse (30000000055), we get a palindrome (85000000058).

The spelling of 55000000003 in words is "fifty-five billion, three", and thus it is an aban number and an uban number.

Divisors: 1 13 169 325443787 4230769231 55000000003