55000003 has 4 divisors (see below), whose sum is σ = 57894760. Its totient is φ = 52105248.

The previous prime is 54999943. The next prime is 55000013. The reversal of 55000003 is 30000055.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30000055 = 5 ⋅6000011.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-55000003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55000013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1447350 + ... + 1447387.

It is an arithmetic number, because the mean of its divisors is an integer number (14473690).

Almost surely, 2^55000003 is an apocalyptic number.

55000003 is a deficient number, since it is larger than the sum of its proper divisors (2894757).

55000003 is a wasteful number, since it uses less digits than its factorization.

55000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2894756.

The product of its (nonzero) digits is 75, while the sum is 13.

The square root of 55000003 is about 7416.1986893556. The cubic root of 55000003 is about 380.2952529906.

Adding to 55000003 its reverse (30000055), we get a palindrome (85000058).

The spelling of 55000003 in words is "fifty-five million, three", and thus it is an aban number and an uban number.