55005000000031 has 2 divisors, whose sum is σ = 55005000000032. Its totient is φ = 55005000000030.

The previous prime is 55005000000023. The next prime is 55005000000053. The reversal of 55005000000031 is 13000000050055.

55005000000031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55005000000031 - 2³ = 55005000000023 is a prime.

It is a super-2 number, since 2×55005000000031² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 55004999999945 and 55005000000008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55005000000001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27502500000015 + 27502500000016.

It is an arithmetic number, because the mean of its divisors is an integer number (27502500000016).

Almost surely, 2^{55005000000031} is an apocalyptic number.

55005000000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

55005000000031 is an equidigital number, since it uses as much as digits as its factorization.

55005000000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 375, while the sum is 19.

Adding to 55005000000031 its reverse (13000000050055), we get a palindrome (68005000050086).

The spelling of 55005000000031 in words is "fifty-five trillion, five billion, thirty-one", and thus it is an aban number and an uban number.