Base | Representation |
---|---|
bin | 110011001110100011… |
… | …011011001101010111 |
3 | 12020222101121112122001 |
4 | 303032203123031113 |
5 | 1400122240004120 |
6 | 41134032020131 |
7 | 3655034535022 |
oct | 631643331527 |
9 | 166871545561 |
10 | 55005000535 |
11 | 21366986031 |
12 | a7b1091647 |
13 | 525795c6c4 |
14 | 293b3341b9 |
15 | 166de87e0a |
hex | cce8db357 |
55005000535 has 4 divisors (see below), whose sum is σ = 66006000648. Its totient is φ = 44004000424.
The previous prime is 55005000529. The next prime is 55005000559. The reversal of 55005000535 is 53500050055.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53500050055 = 5 ⋅10700010011.
It is a cyclic number.
It is not a de Polignac number, because 55005000535 - 215 = 55004967767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5500500049 + ... + 5500500058.
It is an arithmetic number, because the mean of its divisors is an integer number (16501500162).
Almost surely, 255005000535 is an apocalyptic number.
55005000535 is a deficient number, since it is larger than the sum of its proper divisors (11001000113).
55005000535 is a wasteful number, since it uses less digits than its factorization.
55005000535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11001000112.
The product of its (nonzero) digits is 9375, while the sum is 28.
The spelling of 55005000535 in words is "fifty-five billion, five million, five hundred thirty-five", and thus it is an aban number.
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