Base | Representation |
---|---|
bin | 11001000000110111110100… |
… | …10001001100110000010111 |
3 | 21012202110221100120212111211 |
4 | 30200123322101030300113 |
5 | 24202202331300132041 |
6 | 312553111213442251 |
7 | 14405006543433535 |
oct | 1440337221146027 |
9 | 235673840525454 |
10 | 55005550005271 |
11 | 165877a4a93768 |
12 | 620453b4a0387 |
13 | 2490002588818 |
14 | d823d6103155 |
15 | 655c4972c481 |
hex | 3206fa44cc17 |
55005550005271 has 2 divisors, whose sum is σ = 55005550005272. Its totient is φ = 55005550005270.
The previous prime is 55005550005257. The next prime is 55005550005311. The reversal of 55005550005271 is 17250005550055.
It is an a-pointer prime, because the next prime (55005550005311) can be obtained adding 55005550005271 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55005550005271 - 25 = 55005550005239 is a prime.
It is a super-2 number, since 2×550055500052712 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55005550005251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27502775002635 + 27502775002636.
It is an arithmetic number, because the mean of its divisors is an integer number (27502775002636).
Almost surely, 255005550005271 is an apocalyptic number.
55005550005271 is a deficient number, since it is larger than the sum of its proper divisors (1).
55005550005271 is an equidigital number, since it uses as much as digits as its factorization.
55005550005271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 218750, while the sum is 40.
The spelling of 55005550005271 in words is "fifty-five trillion, five billion, five hundred fifty million, five thousand, two hundred seventy-one".
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