55007111253 has 4 divisors (see below), whose sum is σ = 73342815008. Its totient is φ = 36671407500.

The previous prime is 55007111251. The next prime is 55007111297. The reversal of 55007111253 is 35211170055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 55007111253 - 2¹ = 55007111251 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 55007111253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55007111251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9167851873 + ... + 9167851878.

It is an arithmetic number, because the mean of its divisors is an integer number (18335703752).

Almost surely, 2^55007111253 is an apocalyptic number.

It is an amenable number.

55007111253 is a deficient number, since it is larger than the sum of its proper divisors (18335703755).

55007111253 is a wasteful number, since it uses less digits than its factorization.

55007111253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18335703754.

The product of its (nonzero) digits is 5250, while the sum is 30.

The spelling of 55007111253 in words is "fifty-five billion, seven million, one hundred eleven thousand, two hundred fifty-three".