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550101115 = 5110020223
BaseRepresentation
bin100000110010011…
…110000001111011
31102100010000212101
4200302132001323
52111311213430
6130330324231
716426532224
oct4062360173
91370100771
10550101115
11262577123
12134289677
1389c77525
14530b824b
1533462dca
hex20c9e07b

550101115 has 4 divisors (see below), whose sum is σ = 660121344. Its totient is φ = 440080888.

The previous prime is 550101109. The next prime is 550101119. The reversal of 550101115 is 511101055.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 550101115 - 27 = 550100987 is a prime.

It is a super-2 number, since 2×5501011152 = 605222473448486450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 550101092 and 550101101.

It is not an unprimeable number, because it can be changed into a prime (550101119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55010107 + ... + 55010116.

It is an arithmetic number, because the mean of its divisors is an integer number (165030336).

Almost surely, 2550101115 is an apocalyptic number.

550101115 is a deficient number, since it is larger than the sum of its proper divisors (110020229).

550101115 is a wasteful number, since it uses less digits than its factorization.

550101115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110020228.

The product of its (nonzero) digits is 125, while the sum is 19.

The square root of 550101115 is about 23454.2344790871. The cubic root of 550101115 is about 819.3714770212.

The spelling of 550101115 in words is "five hundred fifty million, one hundred one thousand, one hundred fifteen".

Divisors: 1 5 110020223 550101115