Base | Representation |
---|---|
bin | 101000000001110000010… |
… | …0110001000011000001111 |
3 | 201110220212212212100122102 |
4 | 1100003200212020120033 |
5 | 1210113204003343210 |
6 | 15411135133305315 |
7 | 1105312664262404 |
oct | 120034046103017 |
9 | 21426785770572 |
10 | 5501326231055 |
11 | 1831110268a86 |
12 | 74a23b03523b |
13 | 30ba07c02635 |
14 | 1503a0b982ab |
15 | 9817e9c6ea5 |
hex | 500e098860f |
5501326231055 has 8 divisors (see below), whose sum is σ = 6949043660400. Its totient is φ = 4169426196096.
The previous prime is 5501326231039. The next prime is 5501326231081.
5501326231055 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5501326231055 - 24 = 5501326231039 is a prime.
It is a super-3 number, since 3×55013262310553 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28954348490 + ... + 28954348679.
It is an arithmetic number, because the mean of its divisors is an integer number (868630457550).
Almost surely, 25501326231055 is an apocalyptic number.
5501326231055 is a deficient number, since it is larger than the sum of its proper divisors (1447717429345).
5501326231055 is a wasteful number, since it uses less digits than its factorization.
5501326231055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57908697193.
The product of its (nonzero) digits is 135000, while the sum is 38.
The spelling of 5501326231055 in words is "five trillion, five hundred one billion, three hundred twenty-six million, two hundred thirty-one thousand, fifty-five".
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