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55015245301 = 232391967187
BaseRepresentation
bin110011001111001010…
…100000010111110101
312021000002220000210211
4303033022200113311
51400132400322201
641135035345421
73655220604112
oct631712402765
9167002800724
1055015245301
1121371743085
12a7b45b2271
135259b087b3
14293c83d909
15166ed0d651
hexccf2a05f5

55015245301 has 4 divisors (see below), whose sum is σ = 57407212512. Its totient is φ = 52623278092.

The previous prime is 55015245293. The next prime is 55015245319. The reversal of 55015245301 is 10354251055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55015245301 - 23 = 55015245293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55015245391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1195983571 + ... + 1195983616.

It is an arithmetic number, because the mean of its divisors is an integer number (14351803128).

Almost surely, 255015245301 is an apocalyptic number.

It is an amenable number.

55015245301 is a deficient number, since it is larger than the sum of its proper divisors (2391967211).

55015245301 is a wasteful number, since it uses less digits than its factorization.

55015245301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2391967210.

The product of its (nonzero) digits is 15000, while the sum is 31.

Adding to 55015245301 its reverse (10354251055), we get a palindrome (65369496356).

The spelling of 55015245301 in words is "fifty-five billion, fifteen million, two hundred forty-five thousand, three hundred one".

Divisors: 1 23 2391967187 55015245301