Base | Representation |
---|---|
bin | 10000000001001101010… |
… | …01000110101000001111 |
3 | 1221121200121110110121111 |
4 | 20000212221012220033 |
5 | 33004211423420101 |
6 | 1100504022312451 |
7 | 54523345565611 |
oct | 10004651065017 |
9 | 1847617413544 |
10 | 550404123151 |
11 | 1a2474862223 |
12 | 8a809288727 |
13 | 3cb97843a0c |
14 | 1c8d54acdb1 |
15 | e4b5c03251 |
hex | 8026a46a0f |
550404123151 has 2 divisors, whose sum is σ = 550404123152. Its totient is φ = 550404123150.
The previous prime is 550404123149. The next prime is 550404123163. The reversal of 550404123151 is 151321404055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 550404123151 - 21 = 550404123149 is a prime.
Together with 550404123149, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550404123131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275202061575 + 275202061576.
It is an arithmetic number, because the mean of its divisors is an integer number (275202061576).
Almost surely, 2550404123151 is an apocalyptic number.
550404123151 is a deficient number, since it is larger than the sum of its proper divisors (1).
550404123151 is an equidigital number, since it uses as much as digits as its factorization.
550404123151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 550404123151 in words is "five hundred fifty billion, four hundred four million, one hundred twenty-three thousand, one hundred fifty-one".
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