Base | Representation |
---|---|
bin | 110011010000101101… |
… | …100100011010010111 |
3 | 12021001220202101022022 |
4 | 303100231210122113 |
5 | 1400211022322403 |
6 | 41141404123355 |
7 | 3655654412651 |
oct | 632055443227 |
9 | 167056671268 |
10 | 55041214103 |
11 | 2138536a8a7 |
12 | a80123655b |
13 | 52622cb955 |
14 | 294207d6d1 |
15 | 167223cd38 |
hex | cd0b64697 |
55041214103 has 4 divisors (see below), whose sum is σ = 55546179480. Its totient is φ = 54536248728.
The previous prime is 55041214061. The next prime is 55041214139. The reversal of 55041214103 is 30141214055.
55041214103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30141214055 = 5 ⋅6028242811.
It is a cyclic number.
It is not a de Polignac number, because 55041214103 - 226 = 54974105239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55041214603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252482525 + ... + 252482742.
It is an arithmetic number, because the mean of its divisors is an integer number (13886544870).
Almost surely, 255041214103 is an apocalyptic number.
55041214103 is a deficient number, since it is larger than the sum of its proper divisors (504965377).
55041214103 is a wasteful number, since it uses less digits than its factorization.
55041214103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 504965376.
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 55041214103 its reverse (30141214055), we get a palindrome (85182428158).
The spelling of 55041214103 in words is "fifty-five billion, forty-one million, two hundred fourteen thousand, one hundred three".
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