Base | Representation |
---|---|
bin | 11001000001111101110011… |
… | …01111011111110000100111 |
3 | 21012220001220211011202211011 |
4 | 30200332321233133300213 |
5 | 24203311303231242210 |
6 | 313022243342523051 |
7 | 14410506610316566 |
oct | 1440767157376047 |
9 | 235801824152734 |
10 | 55043122134055 |
11 | 165a1725523170 |
12 | 620b886296487 |
13 | 249370c6443a3 |
14 | d8415c077bdd |
15 | 656be7ed4d8a |
hex | 320fb9bdfc27 |
55043122134055 has 32 divisors (see below), whose sum is σ = 72485853168960. Its totient is φ = 39792887009280.
The previous prime is 55043122134023. The next prime is 55043122134233.
55043122134055 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55043122134055 - 25 = 55043122134023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55043122133999 and 55043122134017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 53276631 + ... + 54299959.
It is an arithmetic number, because the mean of its divisors is an integer number (2265182911530).
Almost surely, 255043122134055 is an apocalyptic number.
55043122134055 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55043122134055 is a deficient number, since it is larger than the sum of its proper divisors (17442731034905).
55043122134055 is a wasteful number, since it uses less digits than its factorization.
55043122134055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1029171.
The product of its (nonzero) digits is 360000, while the sum is 40.
It can be divided in two parts, 5504312 and 2134055, that added together give a palindrome (7638367).
The spelling of 55043122134055 in words is "fifty-five trillion, forty-three billion, one hundred twenty-two million, one hundred thirty-four thousand, fifty-five".
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