Base | Representation |
---|---|
bin | 10000000001010000110… |
… | …01011000001001010111 |
3 | 1221121202122211202120010 |
4 | 20000220121120021113 |
5 | 33004241442230111 |
6 | 1100510553211303 |
7 | 54524154010053 |
oct | 10005031301127 |
9 | 1847678752503 |
10 | 550433555031 |
11 | 1a248a434898 |
12 | 8a817100b33 |
13 | 3cba097a229 |
14 | 1c8d9370c63 |
15 | e4b85b8aa6 |
hex | 8028658257 |
550433555031 has 8 divisors (see below), whose sum is σ = 765820598400. Its totient is φ = 351001107512.
The previous prime is 550433555011. The next prime is 550433555059. The reversal of 550433555031 is 130555334055.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 550433555031 - 217 = 550433423959 is a prime.
It is a super-2 number, since 2×5504335550312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (550433555011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3988648881 + ... + 3988649018.
It is an arithmetic number, because the mean of its divisors is an integer number (95727574800).
Almost surely, 2550433555031 is an apocalyptic number.
550433555031 is a deficient number, since it is larger than the sum of its proper divisors (215387043369).
550433555031 is a wasteful number, since it uses less digits than its factorization.
550433555031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7977297925.
The product of its (nonzero) digits is 337500, while the sum is 39.
Adding to 550433555031 its reverse (130555334055), we get a palindrome (680988889086).
The spelling of 550433555031 in words is "five hundred fifty billion, four hundred thirty-three million, five hundred fifty-five thousand, thirty-one".
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