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55047150581 is a prime number
BaseRepresentation
bin110011010001000100…
…001101101111110101
312021002022220222121212
4303101010031233311
51400214032304311
641142135251205
73656056026323
oct632104155765
9167068828555
1055047150581
1121388754a85
12a803219b05
1352635c9a67
142942b86d13
151672a11c8b
hexcd110dbf5

55047150581 has 2 divisors, whose sum is σ = 55047150582. Its totient is φ = 55047150580.

The previous prime is 55047150547. The next prime is 55047150583. The reversal of 55047150581 is 18505174055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53886658225 + 1160492356 = 232135^2 + 34066^2 .

It is a cyclic number.

It is not a de Polignac number, because 55047150581 - 230 = 53973408757 is a prime.

It is a super-2 number, since 2×550471505812 (a number of 22 digits) contains 22 as substring.

Together with 55047150583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55047150583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27523575290 + 27523575291.

It is an arithmetic number, because the mean of its divisors is an integer number (27523575291).

Almost surely, 255047150581 is an apocalyptic number.

It is an amenable number.

55047150581 is a deficient number, since it is larger than the sum of its proper divisors (1).

55047150581 is an equidigital number, since it uses as much as digits as its factorization.

55047150581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 140000, while the sum is 41.

The spelling of 55047150581 in words is "fifty-five billion, forty-seven million, one hundred fifty thousand, five hundred eighty-one".