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55049990703 = 351473565183
BaseRepresentation
bin110011010001001111…
…000011001000101111
312021002112021021112120
4303101033003020233
51400220244200303
641142320204023
73656122125501
oct632117031057
9167075237476
1055049990703
112138a314894
12a804169613
1352640826c6
1429432c5d71
151672dc3553
hexcd13c322f

55049990703 has 8 divisors (see below), whose sum is σ = 73414268928. Its totient is φ = 36692853144.

The previous prime is 55049990693. The next prime is 55049990707. The reversal of 55049990703 is 30709994055.

It is a happy number.

55049990703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 55049990703 - 28 = 55049990447 is a prime.

It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55049990707) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1767151 + ... + 1798032.

It is an arithmetic number, because the mean of its divisors is an integer number (9176783616).

Almost surely, 255049990703 is an apocalyptic number.

55049990703 is a deficient number, since it is larger than the sum of its proper divisors (18364278225).

55049990703 is a wasteful number, since it uses less digits than its factorization.

55049990703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3570333.

The product of its (nonzero) digits is 1530900, while the sum is 51.

The spelling of 55049990703 in words is "fifty-five billion, forty-nine million, nine hundred ninety thousand, seven hundred three".

Divisors: 1 3 5147 15441 3565183 10695549 18349996901 55049990703